• ltxrtquq@lemmy.ml
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    2 months ago

    Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ

    You’re using the derivative of a polar equation as the basis for what a tangent line is. But as the textbook explains, that doesn’t give you a tangent line or describe the slope at that point. I never bothered defining what “tangent” means, but since this seems so important to you why don’t you try coming up with a reasonable definition?

    • wholookshere@lemmy.blahaj.zone
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      2 months ago

      My whole point is that a “straight done”, in general, doesn’t exist in the first place. Because in general definitions are actually really hard.

      It’s not that it’s important to me. It’s that I’ve spent many parts of my day on the phone with the bank, and never should be taken for more than an asshole on the internet. Sorry if you thought I was more invested than that.